GPT答: |
7i24.cn
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The code you provided seems to be incorrect. It looks like you are trying to use the `open` function of the `cap` object from the `grabImage` namespace, but there is no mention of such namespace or object in your code.
If you are trying to open a new video source using OpenCV's VideoCapture class, here is an example of how it can be done:
```cpp
#include <opencv2/opencv.hpp>
int main() {
cv::VideoCapture cap;
std::string new_source = "path_to_video_file.mp4";
// Open the video source
cap.open(new_source);
if (!cap.isOpened()) {
std::cout << "Error opening video file" << std::endl;
return -1;
}
// Rest of your code...
return 0;
}
```
Make sure to replace `"path_to_video_file.mp4"` with the actual path or URL of your video source.
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